What are the solutions to the equation 3x^2-8x=17 ?

The solutions to the equation 3x^2-8x=17 are x=(4+sqrt(67))/3 ,x=(4-sqrt(67))/3

Find the zeros of 3x^2-8x=17

The zeros of 3x^2-8x=17 are x=(4+sqrt(67))/3 ,x=(4-sqrt(67))/3

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3 x^{2} - 8 x = 17

x = \frac{4 + 67}{3}, x = \frac{4 - 67}{3}

Decimal Notation

x = 4.06178 \dots, x = - 1.39511 \dots

Solution steps

3 x^{2} - 8 x = 17

Move

17

to the left side

3 x^{2} - 8 x - 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 3 ( - 17 )}{2 \cdot 3}

(- 8)^{2} - 4 \cdot 3 (- 17) = 267

x_{1, 2} = \frac{- ( - 8 ) \pm 2 67}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 67}{2 \cdot 3}, x_{2} = \frac{- ( - 8 ) - 2 67}{2 \cdot 3}

x = \frac{- ( - 8 ) + 2 67}{2 \cdot 3} : \frac{4 + 67}{3}

x = \frac{- ( - 8 ) - 2 67}{2 \cdot 3} : \frac{4 - 67}{3}

The solutions to the quadratic equation are:

x = \frac{4 + 67}{3}, x = \frac{4 - 67}{3}

\frac{1}{3} + \frac{2}{9}

∣ 4 x ∣ = 28

\frac{25 x ^{4} y ^{7}}{25 x ^{8} y ^{7}}

(\frac{3 x ^{\frac{1}{2}}}{2})^{2}

4 (5)^{2}

What are the solutions to the equation 3x^2-8x=17 ?
The solutions to the equation 3x^2-8x=17 are x=(4+sqrt(67))/3 ,x=(4-sqrt(67))/3
Find the zeros of 3x^2-8x=17
The zeros of 3x^2-8x=17 are x=(4+sqrt(67))/3 ,x=(4-sqrt(67))/3