What are the solutions to the equation x^2+7x-27=0 ?

The solutions to the equation x^2+7x-27=0 are x=(-7+sqrt(157))/2 ,x=(-7-sqrt(157))/2

Find the zeros of x^2+7x-27=0

The zeros of x^2+7x-27=0 are x=(-7+sqrt(157))/2 ,x=(-7-sqrt(157))/2

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x^{2} + 7 x - 27 = 0

x = \frac{- 7 + 157}{2}, x = \frac{- 7 - 157}{2}

Decimal Notation

x = 2.76498 \dots, x = - 9.76498 \dots

Solution steps

x^{2} + 7 x - 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 27 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 27) = 157

x_{1, 2} = \frac{- 7 \pm 157}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 157}{2 \cdot 1}, x_{2} = \frac{- 7 - 157}{2 \cdot 1}

x = \frac{- 7 + 157}{2 \cdot 1} : \frac{- 7 + 157}{2}

x = \frac{- 7 - 157}{2 \cdot 1} : \frac{- 7 - 157}{2}

The solutions to the quadratic equation are:

x = \frac{- 7 + 157}{2}, x = \frac{- 7 - 157}{2}

- 3.1 < x < - 2.7

\frac{20 - 0}{2006 - 1994}

r^{2} - 13 r + 42 = 0

6 x y^{3} + 12 x^{4} y^{4}

\frac{5 + i}{i} + \frac{3 - 4 i}{1 - i}

What are the solutions to the equation x^2+7x-27=0 ?
The solutions to the equation x^2+7x-27=0 are x=(-7+sqrt(157))/2 ,x=(-7-sqrt(157))/2
Find the zeros of x^2+7x-27=0
The zeros of x^2+7x-27=0 are x=(-7+sqrt(157))/2 ,x=(-7-sqrt(157))/2