What are the solutions to the equation x^2+4x+3(0)+10=0 ?

The solutions to the equation x^2+4x+3(0)+10=0 are x=-2+sqrt(6)i,x=-2-sqrt(6)i

Find the zeros of x^2+4x+3(0)+10=0

The zeros of x^2+4x+3(0)+10=0 are x=-2+sqrt(6)i,x=-2-sqrt(6)i

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x^{2} + 4 x + 3 (0) + 10 = 0

x = - 2 + 6 i, x = - 2 - 6 i

Solution steps

x^{2} + 4 x + 3 (0) + 10 = 0

Expand

x^{2} + 4 x + 3 (0) + 10 : x^{2} + 4 x + 10

x^{2} + 4 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 10 : 26 i

x_{1, 2} = \frac{- 4 \pm 2 6 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 6 i}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 6 i}{2 \cdot 1}

x = \frac{- 4 + 2 6 i}{2 \cdot 1} : - 2 + 6 i

x = \frac{- 4 - 2 6 i}{2 \cdot 1} : - 2 - 6 i

The solutions to the quadratic equation are:

x = - 2 + 6 i, x = - 2 - 6 i

- 7 ∣ x + 12 ∣ \leq - 14

\frac{2 2}{3}

2 a^{2} - 9 a - 18

\frac{1}{2} \cdot (\frac{1}{4})^{2}

ln (- 2)

What are the solutions to the equation x^2+4x+3(0)+10=0 ?
The solutions to the equation x^2+4x+3(0)+10=0 are x=-2+sqrt(6)i,x=-2-sqrt(6)i
Find the zeros of x^2+4x+3(0)+10=0
The zeros of x^2+4x+3(0)+10=0 are x=-2+sqrt(6)i,x=-2-sqrt(6)i