What are the solutions to the equation -7d^2+2d+9=0 ?

The solutions to the equation -7d^2+2d+9=0 are d=-1,d= 9/7

Find the zeros of -7d^2+2d+9=0

The zeros of -7d^2+2d+9=0 are d=-1,d= 9/7

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- 7 d^{2} + 2 d + 9 = 0

d = - 1, d = \frac{9}{7}

Decimal Notation

d = - 1, d = 1.28571 \dots

Solution steps

- 7 d^{2} + 2 d + 9 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 7 ) \cdot 9}{2 ( - 7 )}

2^{2} - 4 (- 7) \cdot 9 = 16

d_{1, 2} = \frac{- 2 \pm 16}{2 ( - 7 )}

Separate the solutions

d_{1} = \frac{- 2 + 16}{2 ( - 7 )}, d_{2} = \frac{- 2 - 16}{2 ( - 7 )}

d = \frac{- 2 + 16}{2 ( - 7 )} : - 1

d = \frac{- 2 - 16}{2 ( - 7 )} : \frac{9}{7}

The solutions to the quadratic equation are:

d = - 1, d = \frac{9}{7}

108

\frac{x ^{- 1}}{x ^{- 2} + y ^{- 6}}

5 x + 5 > 2 x + 2

9^{\frac{1}{3}} \cdot 8 1^{\frac{1}{3}}

y + 5 > 9

What are the solutions to the equation -7d^2+2d+9=0 ?
The solutions to the equation -7d^2+2d+9=0 are d=-1,d= 9/7
Find the zeros of -7d^2+2d+9=0
The zeros of -7d^2+2d+9=0 are d=-1,d= 9/7