What is ((a^2-b^2)/(ab)}{\frac{a-b)/b} ?

The solution to ((a^2-b^2)/(ab)}{\frac{a-b)/b} is (a+b)/a

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simplify ((a^2-b^2)/(ab)}{\frac{a-b)/b}

simplify

\frac{\frac{a ^{2} - b ^{2}}{ab}}{\frac{a - b}{b}}

\frac{a + b}{a}

Solution steps

\frac{\frac{a ^{2} - b ^{2}}{ab}}{\frac{a - b}{b}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( a ^{2} - b ^{2} ) b}{ab ( a - b )}

Cancel the common factor:

b

= \frac{a ^{2} - b ^{2}}{a ( a - b )}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

a^{2} - b^{2} = (a + b) (a - b)

= \frac{( a + b ) ( a - b )}{a ( a - b )}

Cancel the common factor:

a - b

= \frac{a + b}{a}

17 + 3 x \leq - 4

\frac{x ^{- 7}}{x ^{- 3}}

3 n^{2} + 8 n + 5

lo g_{12} (144)

(v + \frac{1}{5})^{2} - 9 = 0

What is ((a^2-b^2)/(ab)}{\frac{a-b)/b} ?
The solution to ((a^2-b^2)/(ab)}{\frac{a-b)/b} is (a+b)/a