What is (-2x^{-1}y^2)(5x^2y)^{-2} ?

The solution to (-2x^{-1}y^2)(5x^2y)^{-2} is -2/(25x^5)

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simplify (-2x^{-1}y^2)(5x^2y)^{-2}

simplify

(- 2 x^{- 1} y^{2}) (5 x^{2} y)^{- 2}

- \frac{2}{25 x ^{5}}

Solution steps

(- 2 x^{- 1} y^{2}) (5 x^{2} y)^{- 2}

Apply rule:

(- a) = - a

(- 2 x^{- 1} y^{2}) = - 2 x^{- 1} y^{2}

= - 2 x^{- 1} y^{2} (5 x^{2} y)^{- 2}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

x^{- 1} = \frac{1}{x}

= - 2 \cdot \frac{1}{x} y^{2} (5 x^{2} y)^{- 2}

Simplify

(5 x^{2} y)^{- 2} : \frac{1}{25 x ^{4} y ^{2}}

= - 2 \cdot \frac{1}{x} y^{2} \frac{1}{25 x ^{4} y ^{2}}

Apply the fraction rule:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= - \frac{2 \cdot 1 \cdot y ^{2} \cdot 1}{x \cdot 25 x ^{4} y ^{2}}

Multiply the numbers:

2 \cdot 1 \cdot 1 = 2

= - \frac{2 y ^{2}}{x \cdot 25 x ^{4} y ^{2}}

Cancel the common factor:

y^{2}

= - \frac{2}{x \cdot 25 x ^{4}}

Simplify

x x^{4} : x^{5}

= - \frac{2}{x ^{5} \cdot 25}

= - \frac{2}{25 x ^{5}}

304

t^{4} - 81

d^{2} - 4 d + 5 = d

(8 y^{3}) (- 3 x^{2} y^{2}) (\frac{3}{8} x y^{4})

x = 22 - 33 e^{- l n (\frac{10}{33}) (4)}

What is (-2x^{-1}y^2)(5x^2y)^{-2} ?
The solution to (-2x^{-1}y^2)(5x^2y)^{-2} is -2/(25x^5)