What are the solutions to the equation x^2+2x=-7 ?

The solutions to the equation x^2+2x=-7 are x=-1+sqrt(6)i,x=-1-sqrt(6)i

Find the zeros of x^2+2x=-7

The zeros of x^2+2x=-7 are x=-1+sqrt(6)i,x=-1-sqrt(6)i

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x^{2} + 2 x = - 7

x = - 1 + 6 i, x = - 1 - 6 i

Solution steps

x^{2} + 2 x = - 7

Move

7

to the left side

x^{2} + 2 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 7 : 26 i

x_{1, 2} = \frac{- 2 \pm 2 6 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 6 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 6 i}{2 \cdot 1}

x = \frac{- 2 + 2 6 i}{2 \cdot 1} : - 1 + 6 i

x = \frac{- 2 - 2 6 i}{2 \cdot 1} : - 1 - 6 i

The solutions to the quadratic equation are:

x = - 1 + 6 i, x = - 1 - 6 i

\frac{2 + 2}{2 - 1}

3 x^{2} - 48 y^{2}

7 x + 2 x \geq 21 - 3

\frac{1}{4} (x - 1) - \frac{1}{5} (x - 3) = 0.6

x^{2} + 6 x - 27 = 0

What are the solutions to the equation x^2+2x=-7 ?
The solutions to the equation x^2+2x=-7 are x=-1+sqrt(6)i,x=-1-sqrt(6)i
Find the zeros of x^2+2x=-7
The zeros of x^2+2x=-7 are x=-1+sqrt(6)i,x=-1-sqrt(6)i