What are the solutions to the equation sqrt(5)^2+b^2=6^2 ?

The solutions to the equation sqrt(5)^2+b^2=6^2 are b=sqrt(31),b=-sqrt(31)

Find the zeros of sqrt(5)^2+b^2=6^2

The zeros of sqrt(5)^2+b^2=6^2 are b=sqrt(31),b=-sqrt(31)

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5^{2} + b^{2} = 6^{2}

b = 31, b = - 31

Decimal Notation

b = 5.56776 \dots, b = - 5.56776 \dots

Solution steps

(5)^{2} + b^{2} = 6^{2}

Move

5^{2}

to the right side

b^{2} = 31

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 31, b = - 31

15 x \cdot 25 (8000 - x) = 161000

2 x^{2} - x = 10

(x - 8) (x - 6) = 0

- 12 x \leq 60

2 (\frac{1}{5} m - \frac{2}{5}) + \frac{3}{5}

What are the solutions to the equation sqrt(5)^2+b^2=6^2 ?
The solutions to the equation sqrt(5)^2+b^2=6^2 are b=sqrt(31),b=-sqrt(31)
Find the zeros of sqrt(5)^2+b^2=6^2
The zeros of sqrt(5)^2+b^2=6^2 are b=sqrt(31),b=-sqrt(31)