What are the solutions to the equation 78.2^2+41.3^2=c^2 ?

The solutions to the equation 78.2^2+41.3^2=c^2 are c=(sqrt(782093))/(10),c=-(sqrt(782093))/(10)

Find the zeros of 78.2^2+41.3^2=c^2

The zeros of 78.2^2+41.3^2=c^2 are c=(sqrt(782093))/(10),c=-(sqrt(782093))/(10)

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78. 2^{2} + 41. 3^{2} = c^{2}

c = \frac{782093}{10}, c = - \frac{782093}{10}

Decimal Notation

c = 88.43602 \dots, c = - 88.43602 \dots

Solution steps

78. 2^{2} + 41. 3^{2} = c^{2}

Switch sides

c^{2} = 78. 2^{2} + 41. 3^{2}

Simplify

78. 2^{2} + 41. 3^{2} : 7820.93

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 7820.93, c = - 7820.93

7820.93 = \frac{782093}{10}

- 7820.93 = - \frac{782093}{10}

c = \frac{782093}{10}, c = - \frac{782093}{10}

\frac{x y}{30} - \frac{x y}{12}

(x - 1)^{2} - 4 (x - 1) - 32 = 0

x^{2} - 3 x - 28 = 0

81 \cdot 3

\frac{11}{2}

What are the solutions to the equation 78.2^2+41.3^2=c^2 ?
The solutions to the equation 78.2^2+41.3^2=c^2 are c=(sqrt(782093))/(10),c=-(sqrt(782093))/(10)
Find the zeros of 78.2^2+41.3^2=c^2
The zeros of 78.2^2+41.3^2=c^2 are c=(sqrt(782093))/(10),c=-(sqrt(782093))/(10)