What are the solutions to the equation 1-0.6L+0.08L^2=0 ?

The solutions to the equation 1-0.6L+0.08L^2=0 are L=5,L= 5/2

Find the zeros of 1-0.6L+0.08L^2=0

The zeros of 1-0.6L+0.08L^2=0 are L=5,L= 5/2

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1 - 0.6 L + 0.08 L^{2} = 0

L = 5, L = \frac{5}{2}

Decimal Notation

L = 5, L = 2.5

Solution steps

1 - 0.6 L + 0.08 L^{2} = 0

Multiply both sides by

100

100 - 60 L + 8 L^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

8 L^{2} - 60 L + 100 = 0

Solve with the quadratic formula

L_{1, 2} = \frac{- ( - 60 ) \pm ( - 60 ) ^{2} - 4 \cdot 8 \cdot 100}{2 \cdot 8}

(- 60)^{2} - 4 \cdot 8 \cdot 100 = 20

L_{1, 2} = \frac{- ( - 60 ) \pm 20}{2 \cdot 8}

Separate the solutions

L_{1} = \frac{- ( - 60 ) + 20}{2 \cdot 8}, L_{2} = \frac{- ( - 60 ) - 20}{2 \cdot 8}

L = \frac{- ( - 60 ) + 20}{2 \cdot 8} : 5

L = \frac{- ( - 60 ) - 20}{2 \cdot 8} : \frac{5}{2}

The solutions to the quadratic equation are:

L = 5, L = \frac{5}{2}

40 = 4 t^{2} + 12 t

- 32 c \leq 0

6 x^{2} = 375

\frac{5 a ^{- 5} b ^{4}}{15 a ^{2} b ^{- 6}}

(\frac{1}{81})^{\frac{1}{4}}

What are the solutions to the equation 1-0.6L+0.08L^2=0 ?
The solutions to the equation 1-0.6L+0.08L^2=0 are L=5,L= 5/2
Find the zeros of 1-0.6L+0.08L^2=0
The zeros of 1-0.6L+0.08L^2=0 are L=5,L= 5/2