What are the solutions to the equation x^2+8x+16=25 ?

The solutions to the equation x^2+8x+16=25 are x=1,x=-9

Find the zeros of x^2+8x+16=25

The zeros of x^2+8x+16=25 are x=1,x=-9

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x^{2} + 8 x + 16 = 25

x = 1, x = - 9

Solution steps

x^{2} + 8 x + 16 = 25

Move

25

to the left side

x^{2} + 8 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 9) = 10

x_{1, 2} = \frac{- 8 \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 10}{2 \cdot 1}, x_{2} = \frac{- 8 - 10}{2 \cdot 1}

x = \frac{- 8 + 10}{2 \cdot 1} : 1

x = \frac{- 8 - 10}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 1, x = - 9

- 16 t^{2} + 1502 t + 6.5 = 0

2 x + 3 > 7

x^{4} - 1 = 0

\frac{49}{144}

7 x^{2} - 31 x + 12

What are the solutions to the equation x^2+8x+16=25 ?
The solutions to the equation x^2+8x+16=25 are x=1,x=-9
Find the zeros of x^2+8x+16=25
The zeros of x^2+8x+16=25 are x=1,x=-9