What are the solutions to the equation 0.8x^2-0.8x+0.24=0 ?

The solutions to the equation 0.8x^2-0.8x+0.24=0 are x= 1/2+i(sqrt(5))/(10),x= 1/2-i(sqrt(5))/(10)

Find the zeros of 0.8x^2-0.8x+0.24=0

The zeros of 0.8x^2-0.8x+0.24=0 are x= 1/2+i(sqrt(5))/(10),x= 1/2-i(sqrt(5))/(10)

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0.8 x^{2} - 0.8 x + 0.24 = 0

x = \frac{1}{2} + i \frac{5}{10}, x = \frac{1}{2} - i \frac{5}{10}

Solution steps

0.8 x^{2} - 0.8 x + 0.24 = 0

Multiply both sides by

100

80 x^{2} - 80 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 80 ) \pm ( - 80 ) ^{2} - 4 \cdot 80 \cdot 24}{2 \cdot 80}

Simplify

(- 80)^{2} - 4 \cdot 80 \cdot 24 : 165 i

x_{1, 2} = \frac{- ( - 80 ) \pm 16 5 i}{2 \cdot 80}

Separate the solutions

x_{1} = \frac{- ( - 80 ) + 16 5 i}{2 \cdot 80}, x_{2} = \frac{- ( - 80 ) - 16 5 i}{2 \cdot 80}

x = \frac{- ( - 80 ) + 16 5 i}{2 \cdot 80} : \frac{1}{2} + i \frac{5}{10}

x = \frac{- ( - 80 ) - 16 5 i}{2 \cdot 80} : \frac{1}{2} - i \frac{5}{10}

The solutions to the quadratic equation are:

x = \frac{1}{2} + i \frac{5}{10}, x = \frac{1}{2} - i \frac{5}{10}

4 = e^{2}

\frac{2 x - 5}{7} = 3

\frac{y}{2} + \frac{4}{5} \leq 3

- \frac{1}{2} c + 26 < 22

6 x^{2} + 24 x - 126

What are the solutions to the equation 0.8x^2-0.8x+0.24=0 ?
The solutions to the equation 0.8x^2-0.8x+0.24=0 are x= 1/2+i(sqrt(5))/(10),x= 1/2-i(sqrt(5))/(10)
Find the zeros of 0.8x^2-0.8x+0.24=0
The zeros of 0.8x^2-0.8x+0.24=0 are x= 1/2+i(sqrt(5))/(10),x= 1/2-i(sqrt(5))/(10)