What are the solutions to the equation 4x^2+4x-4=0 ?

The solutions to the equation 4x^2+4x-4=0 are x=(-1+sqrt(5))/2 ,x=-(1+sqrt(5))/2

Find the zeros of 4x^2+4x-4=0

The zeros of 4x^2+4x-4=0 are x=(-1+sqrt(5))/2 ,x=-(1+sqrt(5))/2

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4 x^{2} + 4 x - 4 = 0

x = \frac{- 1 + 5}{2}, x = - \frac{1 + 5}{2}

Decimal Notation

x = 0.61803 \dots, x = - 1.61803 \dots

Solution steps

4 x^{2} + 4 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 ( - 4 )}{2 \cdot 4}

4^{2} - 4 \cdot 4 (- 4) = 45

x_{1, 2} = \frac{- 4 \pm 4 5}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 4 + 4 5}{2 \cdot 4}, x_{2} = \frac{- 4 - 4 5}{2 \cdot 4}

x = \frac{- 4 + 4 5}{2 \cdot 4} : \frac{- 1 + 5}{2}

x = \frac{- 4 - 4 5}{2 \cdot 4} : - \frac{1 + 5}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 5}{2}, x = - \frac{1 + 5}{2}

1 5^{0}

- \frac{3}{2} (2)^{- 1}

f (g (x))

- \frac{6}{8}

What are the solutions to the equation 4x^2+4x-4=0 ?
The solutions to the equation 4x^2+4x-4=0 are x=(-1+sqrt(5))/2 ,x=-(1+sqrt(5))/2
Find the zeros of 4x^2+4x-4=0
The zeros of 4x^2+4x-4=0 are x=(-1+sqrt(5))/2 ,x=-(1+sqrt(5))/2