What are the solutions to the equation (x^2)/(90)+(19x)/(90)+1=0 ?

The solutions to the equation (x^2)/(90)+(19x)/(90)+1=0 are x=-9,x=-10

Find the zeros of (x^2)/(90)+(19x)/(90)+1=0

The zeros of (x^2)/(90)+(19x)/(90)+1=0 are x=-9,x=-10

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\frac{x ^{2}}{90} + \frac{19 x}{90} + 1 = 0

x = - 9, x = - 10

Solution steps

\frac{x ^{2}}{90} + \frac{19 x}{90} + 1 = 0

Multiply both sides by

90

x^{2} + 19 x + 90 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 19 \pm 1 9 ^{2} - 4 \cdot 1 \cdot 90}{2 \cdot 1}

1 9^{2} - 4 \cdot 1 \cdot 90 = 1

x_{1, 2} = \frac{- 19 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 19 + 1}{2 \cdot 1}, x_{2} = \frac{- 19 - 1}{2 \cdot 1}

x = \frac{- 19 + 1}{2 \cdot 1} : - 9

x = \frac{- 19 - 1}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = - 9, x = - 10

\frac{5}{4} + \frac{1}{4}

3 x + 5 < 14

x^{2} + 8 x = 88

(- 2 g^{2} h)^{3} (\frac{g}{4 h ^{2}})^{2}

5 n^{2} = 9 n

What are the solutions to the equation (x^2)/(90)+(19x)/(90)+1=0 ?
The solutions to the equation (x^2)/(90)+(19x)/(90)+1=0 are x=-9,x=-10
Find the zeros of (x^2)/(90)+(19x)/(90)+1=0
The zeros of (x^2)/(90)+(19x)/(90)+1=0 are x=-9,x=-10