What are the solutions to the equation x(3x+2)=1 ?

The solutions to the equation x(3x+2)=1 are x= 1/3 ,x=-1

Find the zeros of x(3x+2)=1

The zeros of x(3x+2)=1 are x= 1/3 ,x=-1

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x (3 x + 2) = 1

x = \frac{1}{3}, x = - 1

Decimal Notation

x = 0.33333 \dots, x = - 1

Solution steps

x (3 x + 2) = 1

Expand

x (3 x + 2) : 3 x^{2} + 2 x

3 x^{2} + 2 x = 1

Move

1

to the left side

3 x^{2} + 2 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 3 ( - 1 )}{2 \cdot 3}

2^{2} - 4 \cdot 3 (- 1) = 4

x_{1, 2} = \frac{- 2 \pm 4}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 2 + 4}{2 \cdot 3}, x_{2} = \frac{- 2 - 4}{2 \cdot 3}

x = \frac{- 2 + 4}{2 \cdot 3} : \frac{1}{3}

x = \frac{- 2 - 4}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - 1

\frac{12 x ^{7} y ^{8}}{4 x ^{3} y}

4 (w - 2) - 3 w = 2 (w - 6)

7 (1 + 10 p) + 8 (1 + 6 p)

3 y^{2} = 12 y

\frac{1}{2} p + 7 = \frac{3}{4} p + 9

What are the solutions to the equation x(3x+2)=1 ?
The solutions to the equation x(3x+2)=1 are x= 1/3 ,x=-1
Find the zeros of x(3x+2)=1
The zeros of x(3x+2)=1 are x= 1/3 ,x=-1