What are the solutions to the equation 5x^2+8x+15=0 ?

The solutions to the equation 5x^2+8x+15=0 are x=-4/5+i(sqrt(59))/5 ,x=-4/5-i(sqrt(59))/5

Find the zeros of 5x^2+8x+15=0

The zeros of 5x^2+8x+15=0 are x=-4/5+i(sqrt(59))/5 ,x=-4/5-i(sqrt(59))/5

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5 x^{2} + 8 x + 15 = 0

x = - \frac{4}{5} + i \frac{59}{5}, x = - \frac{4}{5} - i \frac{59}{5}

Solution steps

5 x^{2} + 8 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 5 \cdot 15}{2 \cdot 5}

Simplify

8^{2} - 4 \cdot 5 \cdot 15 : 259 i

x_{1, 2} = \frac{- 8 \pm 2 59 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 8 + 2 59 i}{2 \cdot 5}, x_{2} = \frac{- 8 - 2 59 i}{2 \cdot 5}

x = \frac{- 8 + 2 59 i}{2 \cdot 5} : - \frac{4}{5} + i \frac{59}{5}

x = \frac{- 8 - 2 59 i}{2 \cdot 5} : - \frac{4}{5} - i \frac{59}{5}

The solutions to the quadratic equation are:

x = - \frac{4}{5} + i \frac{59}{5}, x = - \frac{4}{5} - i \frac{59}{5}

(4 + i) (3 + 2 i) (1 - i)

\frac{3}{2} + \frac{1}{3} - \frac{1}{4}

x^{2} - 1 \leq ∣ x + 1 ∣

0.9 t = 1 + t

0 \leq 6 - \frac{3}{2} x \leq 9

What are the solutions to the equation 5x^2+8x+15=0 ?
The solutions to the equation 5x^2+8x+15=0 are x=-4/5+i(sqrt(59))/5 ,x=-4/5-i(sqrt(59))/5
Find the zeros of 5x^2+8x+15=0
The zeros of 5x^2+8x+15=0 are x=-4/5+i(sqrt(59))/5 ,x=-4/5-i(sqrt(59))/5