What are the solutions to the equation -x^2+3x-4=0 ?

The solutions to the equation -x^2+3x-4=0 are x= 3/2-i(sqrt(7))/2 ,x= 3/2+i(sqrt(7))/2

Find the zeros of -x^2+3x-4=0

The zeros of -x^2+3x-4=0 are x= 3/2-i(sqrt(7))/2 ,x= 3/2+i(sqrt(7))/2

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- x^{2} + 3 x - 4 = 0

x = \frac{3}{2} - i \frac{7}{2}, x = \frac{3}{2} + i \frac{7}{2}

Solution steps

- x^{2} + 3 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 1 ) ( - 4 )}{2 ( - 1 )}

Simplify

3^{2} - 4 (- 1) (- 4) : 7 i

x_{1, 2} = \frac{- 3 \pm 7 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 3 + 7 i}{2 ( - 1 )}, x_{2} = \frac{- 3 - 7 i}{2 ( - 1 )}

x = \frac{- 3 + 7 i}{2 ( - 1 )} : \frac{3}{2} - i \frac{7}{2}

x = \frac{- 3 - 7 i}{2 ( - 1 )} : \frac{3}{2} + i \frac{7}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2} - i \frac{7}{2}, x = \frac{3}{2} + i \frac{7}{2}

- \frac{16}{- 2}

0.25 \cdot x + (x + 5) 0.5 + (x + 9) 0.1 = 3.75

8 x + 24 = - 4 (2 x - 6)

6 - 63

\frac{2 x ^{6} y ^{3}}{x ^{2} y ^{7}}

What are the solutions to the equation -x^2+3x-4=0 ?
The solutions to the equation -x^2+3x-4=0 are x= 3/2-i(sqrt(7))/2 ,x= 3/2+i(sqrt(7))/2
Find the zeros of -x^2+3x-4=0
The zeros of -x^2+3x-4=0 are x= 3/2-i(sqrt(7))/2 ,x= 3/2+i(sqrt(7))/2