What are the solutions to the equation 3x^2-6x-18=0 ?

The solutions to the equation 3x^2-6x-18=0 are x=1+sqrt(7),x=1-sqrt(7)

Find the zeros of 3x^2-6x-18=0

The zeros of 3x^2-6x-18=0 are x=1+sqrt(7),x=1-sqrt(7)

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3 x^{2} - 6 x - 18 = 0

x = 1 + 7, x = 1 - 7

Decimal Notation

x = 3.64575 \dots, x = - 1.64575 \dots

Solution steps

3 x^{2} - 6 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 ( - 18 )}{2 \cdot 3}

(- 6)^{2} - 4 \cdot 3 (- 18) = 67

x_{1, 2} = \frac{- ( - 6 ) \pm 6 7}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 6 7}{2 \cdot 3}, x_{2} = \frac{- ( - 6 ) - 6 7}{2 \cdot 3}

x = \frac{- ( - 6 ) + 6 7}{2 \cdot 3} : 1 + 7

x = \frac{- ( - 6 ) - 6 7}{2 \cdot 3} : 1 - 7

The solutions to the quadratic equation are:

x = 1 + 7, x = 1 - 7

5 \cdot \frac{1}{4}

(\frac{2}{5})^{- 3}

(2 x^{2} y^{4}) + (2 x y) - (3 x^{2} y^{2})

21 + 4 (3^{2} - 5)

x - 7 \leq 5 - 3 x < 9 - 5 x

What are the solutions to the equation 3x^2-6x-18=0 ?
The solutions to the equation 3x^2-6x-18=0 are x=1+sqrt(7),x=1-sqrt(7)
Find the zeros of 3x^2-6x-18=0
The zeros of 3x^2-6x-18=0 are x=1+sqrt(7),x=1-sqrt(7)