What are the solutions to the equation -8/3 =4x-2x^2 ?

The solutions to the equation -8/3 =4x-2x^2 are x=-(-3+sqrt(21))/3 ,x=(3+sqrt(21))/3

Find the zeros of -8/3 =4x-2x^2

The zeros of -8/3 =4x-2x^2 are x=-(-3+sqrt(21))/3 ,x=(3+sqrt(21))/3

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- \frac{8}{3} = 4 x - 2 x^{2}

x = - \frac{- 3 + 21}{3}, x = \frac{3 + 21}{3}

Decimal Notation

x = - 0.52752 \dots, x = 2.52752 \dots

Solution steps

- \frac{8}{3} = 4 x - 2 x^{2}

Multiply both sides by

3

- 8 = 12 x - 6 x^{2}

Switch sides

12 x - 6 x^{2} = - 8

Move

8

to the left side

12 x - 6 x^{2} + 8 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 6 x^{2} + 12 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 6 ) \cdot 8}{2 ( - 6 )}

1 2^{2} - 4 (- 6) \cdot 8 = 421

x_{1, 2} = \frac{- 12 \pm 4 21}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- 12 + 4 21}{2 ( - 6 )}, x_{2} = \frac{- 12 - 4 21}{2 ( - 6 )}

x = \frac{- 12 + 4 21}{2 ( - 6 )} : - \frac{- 3 + 21}{3}

x = \frac{- 12 - 4 21}{2 ( - 6 )} : \frac{3 + 21}{3}

The solutions to the quadratic equation are:

x = - \frac{- 3 + 21}{3}, x = \frac{3 + 21}{3}

7 (x + 1) \leq 0

y - (- 99) = 4

(- 27) (328)

∣ 3 x ∣ > - 7

3 < 7

What are the solutions to the equation -8/3 =4x-2x^2 ?
The solutions to the equation -8/3 =4x-2x^2 are x=-(-3+sqrt(21))/3 ,x=(3+sqrt(21))/3
Find the zeros of -8/3 =4x-2x^2
The zeros of -8/3 =4x-2x^2 are x=-(-3+sqrt(21))/3 ,x=(3+sqrt(21))/3