What are the solutions to the equation s^2+6s-16=0 ?

The solutions to the equation s^2+6s-16=0 are s=2,s=-8

Find the zeros of s^2+6s-16=0

The zeros of s^2+6s-16=0 are s=2,s=-8

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s^{2} + 6 s - 16 = 0

s = 2, s = - 8

Solution steps

s^{2} + 6 s - 16 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 16 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 16) = 10

s_{1, 2} = \frac{- 6 \pm 10}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 6 + 10}{2 \cdot 1}, s_{2} = \frac{- 6 - 10}{2 \cdot 1}

s = \frac{- 6 + 10}{2 \cdot 1} : 2

s = \frac{- 6 - 10}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

s = 2, s = - 8

\frac{3}{3}

t - 26 = - 21

\frac{2}{9 - i}

b^{9} - 50 = - 15

(- 4 m^{2} n)^{4} \cdot \frac{1}{6} m^{- 10} n^{- 4}

What are the solutions to the equation s^2+6s-16=0 ?
The solutions to the equation s^2+6s-16=0 are s=2,s=-8
Find the zeros of s^2+6s-16=0
The zeros of s^2+6s-16=0 are s=2,s=-8