What are the solutions to the equation 25x^2-20x+4=45 ?

The solutions to the equation 25x^2-20x+4=45 are x=(2+3sqrt(5))/5 ,x=(2-3sqrt(5))/5

Find the zeros of 25x^2-20x+4=45

The zeros of 25x^2-20x+4=45 are x=(2+3sqrt(5))/5 ,x=(2-3sqrt(5))/5

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25 x^{2} - 20 x + 4 = 45

x = \frac{2 + 3 5}{5}, x = \frac{2 - 3 5}{5}

Decimal Notation

x = 1.74164 \dots, x = - 0.94164 \dots

Solution steps

25 x^{2} - 20 x + 4 = 45

Move

45

to the left side

25 x^{2} - 20 x - 41 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 25 ( - 41 )}{2 \cdot 25}

(- 20)^{2} - 4 \cdot 25 (- 41) = 305

x_{1, 2} = \frac{- ( - 20 ) \pm 30 5}{2 \cdot 25}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 30 5}{2 \cdot 25}, x_{2} = \frac{- ( - 20 ) - 30 5}{2 \cdot 25}

x = \frac{- ( - 20 ) + 30 5}{2 \cdot 25} : \frac{2 + 3 5}{5}

x = \frac{- ( - 20 ) - 30 5}{2 \cdot 25} : \frac{2 - 3 5}{5}

The solutions to the quadratic equation are:

x = \frac{2 + 3 5}{5}, x = \frac{2 - 3 5}{5}

w^{2} = - 9 w

12 + 4 x = 30

2 x^{2} + 11 x + 15

12 = 3 + x

4 m^{2} - 9 n^{2}

What are the solutions to the equation 25x^2-20x+4=45 ?
The solutions to the equation 25x^2-20x+4=45 are x=(2+3sqrt(5))/5 ,x=(2-3sqrt(5))/5
Find the zeros of 25x^2-20x+4=45
The zeros of 25x^2-20x+4=45 are x=(2+3sqrt(5))/5 ,x=(2-3sqrt(5))/5