What are the solutions to the equation 16t^2-23t+8=0 ?

The solutions to the equation 16t^2-23t+8=0 are t=(23+sqrt(17))/(32),t=(23-sqrt(17))/(32)

Find the zeros of 16t^2-23t+8=0

The zeros of 16t^2-23t+8=0 are t=(23+sqrt(17))/(32),t=(23-sqrt(17))/(32)

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16 t^{2} - 23 t + 8 = 0

t = \frac{23 + 17}{32}, t = \frac{23 - 17}{32}

Decimal Notation

t = 0.84759 \dots, t = 0.58990 \dots

Solution steps

16 t^{2} - 23 t + 8 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 23 ) \pm ( - 23 ) ^{2} - 4 \cdot 16 \cdot 8}{2 \cdot 16}

(- 23)^{2} - 4 \cdot 16 \cdot 8 = 17

t_{1, 2} = \frac{- ( - 23 ) \pm 17}{2 \cdot 16}

Separate the solutions

t_{1} = \frac{- ( - 23 ) + 17}{2 \cdot 16}, t_{2} = \frac{- ( - 23 ) - 17}{2 \cdot 16}

t = \frac{- ( - 23 ) + 17}{2 \cdot 16} : \frac{23 + 17}{32}

t = \frac{- ( - 23 ) - 17}{2 \cdot 16} : \frac{23 - 17}{32}

The solutions to the quadratic equation are:

t = \frac{23 + 17}{32}, t = \frac{23 - 17}{32}

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What are the solutions to the equation 16t^2-23t+8=0 ?
The solutions to the equation 16t^2-23t+8=0 are t=(23+sqrt(17))/(32),t=(23-sqrt(17))/(32)
Find the zeros of 16t^2-23t+8=0
The zeros of 16t^2-23t+8=0 are t=(23+sqrt(17))/(32),t=(23-sqrt(17))/(32)