What are the solutions to the equation 6x^2+4x-3=0 ?

The solutions to the equation 6x^2+4x-3=0 are x=(-2+sqrt(22))/6 ,x=-(2+sqrt(22))/6

Find the zeros of 6x^2+4x-3=0

The zeros of 6x^2+4x-3=0 are x=(-2+sqrt(22))/6 ,x=-(2+sqrt(22))/6

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6 x^{2} + 4 x - 3 = 0

x = \frac{- 2 + 22}{6}, x = - \frac{2 + 22}{6}

Decimal Notation

x = 0.44840 \dots, x = - 1.11506 \dots

Solution steps

6 x^{2} + 4 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 6 ( - 3 )}{2 \cdot 6}

4^{2} - 4 \cdot 6 (- 3) = 222

x_{1, 2} = \frac{- 4 \pm 2 22}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 4 + 2 22}{2 \cdot 6}, x_{2} = \frac{- 4 - 2 22}{2 \cdot 6}

x = \frac{- 4 + 2 22}{2 \cdot 6} : \frac{- 2 + 22}{6}

x = \frac{- 4 - 2 22}{2 \cdot 6} : - \frac{2 + 22}{6}

The solutions to the quadratic equation are:

x = \frac{- 2 + 22}{6}, x = - \frac{2 + 22}{6}

\frac{2 x + 6}{x - 2} < 0

∣ 2 b + 6 ∣ = ∣ b + 1 ∣

45 b + 10

1 + 3 z \geq 7

6 x^{2} - 41 x - 7 = 0

What are the solutions to the equation 6x^2+4x-3=0 ?
The solutions to the equation 6x^2+4x-3=0 are x=(-2+sqrt(22))/6 ,x=-(2+sqrt(22))/6
Find the zeros of 6x^2+4x-3=0
The zeros of 6x^2+4x-3=0 are x=(-2+sqrt(22))/6 ,x=-(2+sqrt(22))/6