What are the solutions to the equation 3x^2-x=-4x+60 ?

The solutions to the equation 3x^2-x=-4x+60 are x=4,x=-5

Find the zeros of 3x^2-x=-4x+60

The zeros of 3x^2-x=-4x+60 are x=4,x=-5

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3 x^{2} - x = - 4 x + 60

x = 4, x = - 5

Solution steps

3 x^{2} - x = - 4 x + 60

Move

60

to the left side

3 x^{2} - x - 60 = - 4 x

Move

4 x

to the left side

3 x^{2} + 3 x - 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 3 ( - 60 )}{2 \cdot 3}

3^{2} - 4 \cdot 3 (- 60) = 27

x_{1, 2} = \frac{- 3 \pm 27}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 3 + 27}{2 \cdot 3}, x_{2} = \frac{- 3 - 27}{2 \cdot 3}

x = \frac{- 3 + 27}{2 \cdot 3} : 4

x = \frac{- 3 - 27}{2 \cdot 3} : - 5

The solutions to the quadratic equation are:

x = 4, x = - 5

- \frac{1}{4} + \frac{3}{4}

v^{2} + 10 v + 25 = 0

- 16 t^{2} + 36 t - 20

216 y^{2}

x (2 x + 3) \geq 0

What are the solutions to the equation 3x^2-x=-4x+60 ?
The solutions to the equation 3x^2-x=-4x+60 are x=4,x=-5
Find the zeros of 3x^2-x=-4x+60
The zeros of 3x^2-x=-4x+60 are x=4,x=-5