What is (5n+15)/(4n+8)*(2n+4)/(3n+9) ?

The solution to (5n+15)/(4n+8)*(2n+4)/(3n+9) is 5/6

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simplify (5n+15)/(4n+8)*(2n+4)/(3n+9)

simplify

\frac{5 n + 15}{4 n + 8} \cdot \frac{2 n + 4}{3 n + 9}

\frac{5}{6}

Decimal Notation

0.83333 \dots

Solution steps

\frac{5 n + 15}{4 n + 8} \cdot \frac{2 n + 4}{3 n + 9}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( 5 n + 15 ) ( 2 n + 4 )}{( 4 n + 8 ) ( 3 n + 9 )}

Factor

5 n + 15 : 5 (n + 3)

= \frac{5 ( n + 3 ) ( 2 n + 4 )}{( 4 n + 8 ) ( 3 n + 9 )}

Factor

3 n + 9 : 3 (n + 3)

= \frac{5 ( n + 3 ) ( 2 n + 4 )}{( 4 n + 8 ) \cdot 3 ( n + 3 )}

Cancel the common factor:

n + 3

= \frac{5 ( 2 n + 4 )}{( 4 n + 8 ) \cdot 3}

Factor

2 n + 4 : 2 (n + 2)

= \frac{5 \cdot 2 ( n + 2 )}{( 4 n + 8 ) \cdot 3}

Factor

4 n + 8 : 4 (n + 2)

= \frac{5 \cdot 2 ( n + 2 )}{4 ( n + 2 ) \cdot 3}

Cancel the common factor:

n + 2

= \frac{5 \cdot 2}{4 \cdot 3}

Factor the number:

4 = 2 \cdot 2

= \frac{5 \cdot 2}{2 \cdot 2 \cdot 3}

Cancel the common factor:

2

= \frac{5}{2 \cdot 3}

Multiply the numbers:

2 \cdot 3 = 6

= \frac{5}{6}

\frac{1}{x + 2} \geq 0

ab + 6 b - 2 a - 12

3 r^{2} + 2 r = 0.375

x^{4} + 25 x^{2}

6 - \frac{x}{11} = 7

What is (5n+15)/(4n+8)*(2n+4)/(3n+9) ?
The solution to (5n+15)/(4n+8)*(2n+4)/(3n+9) is 5/6