What are the solutions to the equation 2x^2-10x+12=0 ?

The solutions to the equation 2x^2-10x+12=0 are x=3,x=2

Find the zeros of 2x^2-10x+12=0

The zeros of 2x^2-10x+12=0 are x=3,x=2

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2 x^{2} - 10 x + 12 = 0

x = 3, x = 2

Solution steps

2 x^{2} - 10 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 2 \cdot 12}{2 \cdot 2}

(- 10)^{2} - 4 \cdot 2 \cdot 12 = 2

x_{1, 2} = \frac{- ( - 10 ) \pm 2}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2}{2 \cdot 2}, x_{2} = \frac{- ( - 10 ) - 2}{2 \cdot 2}

x = \frac{- ( - 10 ) + 2}{2 \cdot 2} : 3

x = \frac{- ( - 10 ) - 2}{2 \cdot 2} : 2

The solutions to the quadratic equation are:

x = 3, x = 2

6 h + 16 = 46

4 z^{2} + z + 2 = 0

\frac{5}{9}

14 > 4 + 2 x

\frac{1}{5} x + 7 < 11

What are the solutions to the equation 2x^2-10x+12=0 ?
The solutions to the equation 2x^2-10x+12=0 are x=3,x=2
Find the zeros of 2x^2-10x+12=0
The zeros of 2x^2-10x+12=0 are x=3,x=2