What are the solutions to the equation 2x^2-4=0 ?

The solutions to the equation 2x^2-4=0 are x=sqrt(2),x=-sqrt(2)

Find the zeros of 2x^2-4=0

The zeros of 2x^2-4=0 are x=sqrt(2),x=-sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} - 4 = 0

x = 2, x = - 2

Decimal Notation

x = 1.41421 \dots, x = - 1.41421 \dots

Solution steps

2 x^{2} - 4 = 0

Move

4

to the right side

2 x^{2} = 4

Divide both sides by

2

x^{2} = 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 2, x = - 2

4^{3}

230 + 20 x - 0.5 x^{2} = 0

13 x^{2} - 5 x \leq 0

7 b = 49

2 p^{2} - 10 p + 11 = 0

What are the solutions to the equation 2x^2-4=0 ?
The solutions to the equation 2x^2-4=0 are x=sqrt(2),x=-sqrt(2)
Find the zeros of 2x^2-4=0
The zeros of 2x^2-4=0 are x=sqrt(2),x=-sqrt(2)