What are the solutions to the equation 2x^2+5x-1=0 ?

The solutions to the equation 2x^2+5x-1=0 are x=(-5+sqrt(33))/4 ,x=(-5-sqrt(33))/4

Find the zeros of 2x^2+5x-1=0

The zeros of 2x^2+5x-1=0 are x=(-5+sqrt(33))/4 ,x=(-5-sqrt(33))/4

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2 x^{2} + 5 x - 1 = 0

x = \frac{- 5 + 33}{4}, x = \frac{- 5 - 33}{4}

Decimal Notation

x = 0.18614 \dots, x = - 2.68614 \dots

Solution steps

2 x^{2} + 5 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 ( - 1 )}{2 \cdot 2}

5^{2} - 4 \cdot 2 (- 1) = 33

x_{1, 2} = \frac{- 5 \pm 33}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 5 + 33}{2 \cdot 2}, x_{2} = \frac{- 5 - 33}{2 \cdot 2}

x = \frac{- 5 + 33}{2 \cdot 2} : \frac{- 5 + 33}{4}

x = \frac{- 5 - 33}{2 \cdot 2} : \frac{- 5 - 33}{4}

The solutions to the quadratic equation are:

x = \frac{- 5 + 33}{4}, x = \frac{- 5 - 33}{4}

6 x^{2} - 48 x + 72

d (2 d + 1) - 2 (2 d + 1)

3 x^{2} y - 2 x y^{2} + 3 x y

\frac{c ^{2} + 4 c}{c ^{2} - 4} \cdot \frac{c - 2}{3 c + 12}

4 x^{2} + x + 5 = 0

What are the solutions to the equation 2x^2+5x-1=0 ?
The solutions to the equation 2x^2+5x-1=0 are x=(-5+sqrt(33))/4 ,x=(-5-sqrt(33))/4
Find the zeros of 2x^2+5x-1=0
The zeros of 2x^2+5x-1=0 are x=(-5+sqrt(33))/4 ,x=(-5-sqrt(33))/4