What are the solutions to the equation 4x^2+2=0 ?

The solutions to the equation 4x^2+2=0 are x= 1/(sqrt(2))i,x=-1/(sqrt(2))i

Find the zeros of 4x^2+2=0

The zeros of 4x^2+2=0 are x= 1/(sqrt(2))i,x=-1/(sqrt(2))i

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4 x^{2} + 2 = 0

x = \frac{1}{2} i, x = - \frac{1}{2} i

Solution steps

4 x^{2} + 2 = 0

Move

2

to the right side

4 x^{2} = - 2

Divide both sides by

4

x^{2} = - \frac{1}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{1}{2}, x = - - \frac{1}{2}

- \frac{1}{2} = \frac{1}{2} i

- - \frac{1}{2} = - \frac{1}{2} i

x = \frac{1}{2} i, x = - \frac{1}{2} i

3 x^{2} - 8 = - 2 x

- 6 - 3

5 - 4 x = 5 + 4 x

ln (2^{2})

- 7 (- 1 + 3 a) = 5 (3 - 5 a)

What are the solutions to the equation 4x^2+2=0 ?
The solutions to the equation 4x^2+2=0 are x= 1/(sqrt(2))i,x=-1/(sqrt(2))i
Find the zeros of 4x^2+2=0
The zeros of 4x^2+2=0 are x= 1/(sqrt(2))i,x=-1/(sqrt(2))i